15x^2-4x-3=(3x+1)(5x-3)

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Solution for 15x^2-4x-3=(3x+1)(5x-3) equation: 



15x^2-4x-3=(3x+1)(5x-3)

We move all terms to the left:

15x^2-4x-3-((3x+1)(5x-3))=0

We multiply parentheses ..

15x^2-((+15x^2-9x+5x-3))-4x-3=0



We calculate terms in parentheses: -((+15x^2-9x+5x-3)), so:

(+15x^2-9x+5x-3)

We get rid of parentheses

15x^2-9x+5x-3

We add all the numbers together, and all the variables

15x^2-4x-3

Back to the equation:

-(15x^2-4x-3)



We add all the numbers together, and all the variables

15x^2-4x-(15x^2-4x-3)-3=0

We get rid of parentheses

15x^2-15x^2-4x+4x+3-3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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